151. Reverse Words in a String
A word is defined as a sequence of non-space characters. The words in s
will be separated by at least one space.
Return a string of the words in reverse order concatenated by a single space.
Note that s
may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces.
Example 1:
Input: s = "the sky is blue"
Output: "blue is sky the"
Example 2:
Input: s = " hello world "
Output: "world hello"
Explanation: Your reversed string should not contain leading or trailing spaces.
Example 3:
Input: s = "a good example"
Output: "example good a"
Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string.
Constraints:
1 <= s.length <= 10<sup>4</sup>
s
contains English letters (upper-case and lower-case), digits, and spaces' '
.There is at least one word in
s
.
Solution:
class Solution(object):
def reverseWords(self, s):
length = len(s)
word_positions = [] # To store start and end indices of words
i = 0
# Iterate through the string to identify word boundaries
while i < length:
# Skip leading spaces
while i < length and s[i] == ' ':
i += 1
if i == length:
break
start = i # Start of the word
# Move to the end of the word
while i < length and s[i] != ' ':
i += 1
end = i - 1 # End of the word
# Store the start and end indices of the word
word_positions.append((start, end))
result = []
# Reverse the order of the words and build the result string
for start, end in reversed(word_positions):
word = s[start:end + 1]
result.append(word)
return ' '.join(result)