Skip to main content

Command Palette

Search for a command to run...

110. Balanced Binary Tree

Published
•1 min read•View as Markdown
B
Senior Software Engineer | Backend, Cloud, Data, Machine Learning

Given a binary tree, determine if it is

height-balanced.

Example 1:

Input: root = [3,9,20,null,null,15,7]
Output: true

Example 2:

Input: root = [1,2,2,3,3,null,null,4,4]
Output: false

Example 3:

Input: root = []
Output: true

Constraints:

  • The number of nodes in the tree is in the range [0, 5000].

  • -10<sup>4</sup> <= Node.val <= 10<sup>4</sup>

Solution:

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right

class Solution:
    def isBalanced(self, root: Optional[TreeNode]) -> bool:
        def dfs(root):
            if not root:
                return [True, 0]

            left, right = dfs(root.left), dfs(root.right)
            balanced = left[0] and right[0] and abs(left[1] - right[1]) <= 1
            return [balanced, 1 + max(left[1], right[1])]

        return dfs(root)[0]

More from this blog

yesicbap

437 posts